If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-5x=10x
We move all terms to the left:
3x^2-5x-(10x)=0
We add all the numbers together, and all the variables
3x^2-15x=0
a = 3; b = -15; c = 0;
Δ = b2-4ac
Δ = -152-4·3·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-15}{2*3}=\frac{0}{6} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+15}{2*3}=\frac{30}{6} =5 $
| -3(x-1)+8(x-3)=6x+6-5x | | −20=2(x−9) | | 30=5(1-x) | | −2(x+0.25)+1=5 | | p-1=5p+3p=8 | | 4(7p+3)=-7p-23 | | (x=4)(x^2-x+3)=0 | | −2(x+0.5)+1=5 | | -2(n+4)+6=-4 | | 50=5(x-1) | | 3x+5/4=9 | | 5x+4=8x+10 | | -7(2n+8)-1=-127 | | 5s+2s-4=0 | | 3(x+6)=−12 | | |3x-5|=11 | | 2r=1.8 | | X^4+5x3+9x2+2x-1=0 | | 2x-3=15.3 | | 15+7h=99 | | (X-1)(y-1.5)=24 | | 2(x+4)=3(x–2) | | 0.14(y-2)+0.02y=0.08y-1 | | 2(h—8)—h=h—16 | | 6=-4p+6+5p | | -5+8x=2+4x+41 | | |3x+-4|=|2x+6| | | 2(h-8)h=—16 | | 3c–4c+1=5c+2+3 | | (5x^2-20)-(4x-25)=180 | | 6x+13=9x+23 | | 9e=3e=12 |